Question

Найти производную

y=6^tgx

Answer 1

y=6^{tgx}

y'=(6^tgx)'=6^tgx * ln6 * (tgx)' = 6^tgx * ln6 * 1/Cos²x

Answer 2

$y=6^{tgx}; ,\\(a^{u})'=a^{u}cdot lnacdot u'; ,; a=6; ,; u=tgx\\y'=6^{tgx}cdot ln6cdot (tgx)'=6^{tgx}cdot ln6cdot frac{1}{cos^2x}=frac{6^{tgx}cdot ln6}{cos^2x}$