Question

x^4+2x^3-x-2=0 помогите решить уравнение

Answer 1

$x {}^{3} times (x + 2) - (x - 2) = 0 \ (x + 2)(x {}^{3} - 1) = 0 \ x + 2 = 0 \ x {}^{3} - 1 = 0 \ x = - 2 \ x = 1$

Answer 2

X^4 + 2x^3 - x - 2 = 0

x^3(x + 2) - (x + 2) = 0

(x + 2) (x^3 - 1) = 0

x + 2 = 0      x^3 - 1 = 0

x = - 2         x^3 = 1

                  x = ∛1

                  x = 1

x = {-2; 1}