Question

решите пожалуйста
${x}^{4} - 17 {x}^{2} + 36 = 0$

Answer 1

x^4 -17x^2 +36=0
x^2=t
t^2- 17t + 36=0
D = ( -17)^2 - 4*36= 289 - 144= 145
t1,2= ( 17- |145) /2