Question

найдите tg a если sin a=6/√61 и a принадлежит (0,0,5п)

Answer 1

tgα=sinα/cosα

sin²α+cos²α=1 , cos²α=1-sin²α=1-36/61=61/61-36/61=25/61, α∈(0,π/2)

cosα=√(25/61)=5/√61

tgα=(6/√61)/(5/√61)=6/5