Question

Решите уравнения
(13-3х)²=169
$frac{5}{11}$ *m² =$frac{10}{33}$
(4a + 5)²= 6

Answer 1

$1)(13-3x)x^{2}=169\\13-3x=13\\-3x=0\\x_{1}=0$

или

$13-3x=-13\\-3x=-26\\x_{2} =8frac{2}{3}$

$2)frac{5}{11}m^{2}=frac{10}{33}\\m^{2}=frac{10}{33}:frac{5}{11}=frac{10}{33}*frac{11}{5}=frac{2}{3}\\m_{1}=sqrt{frac{2}{3} }=frac{sqrt{6} }{3}\\m_{2}=-sqrt{frac{2}{3}}=- frac{sqrt{6}}{3}$

$3)(4a+5)^{2}=6\\4a+5=sqrt{6}\\4a=sqrt{6}-5\\a_{1} =frac{sqrt{6}-5 }{4}$

Или

$4a+5=-sqrt{6}\\4a=-sqrt{6} -5\\a_{2}=-frac{sqrt{6}+5 }{4}$

Answer 2

Фото
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