Question

ДАМ 30 БАЛЛОВ!ПОМОГИТЕ!!!
y+2/2+4y−6/7−8−y/14=1
y=(десятичной дробью)

Answer 1

$y + frac{2}{2} + 4y - frac{6}{7 } - 8 - frac{y}{14} = 1 \y + 4y - frac{6}{7} - 8 - frac{y}{14} = 0 \ 5y - frac{62}{7} - frac{y}{14} = 0 \ 69y - 124 = 0 \69y = 124 \ y = frac{124}{69} = 1 times frac{55}{69}$