Question

Найдите сумму целых решений неравенства:

Answer 1

!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$sqrt{4x-x^{2} }>x-5\\1)left { {{x-5<0} atop {4x-x^{2}geq0}} right. \\left { {{x<5} atop {x(x-4)leq 0}} right.$

        +                        -                               +

__________[0]__________[4]______________

                     //////////////////////////

________________________________(5)____

\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

x ∈ [0 ; 4]

$2)left { {{x-5geq0 } atop {4x-x^{2}>(x-5)^{2}}} right.\\left { {{xgeq 5} atop {4x-x^{2}>x^{2}-10x+25}} right. \\left { {{xgeq 5} atop {4x-x^{2}-x^{2} +10x-25>0 }} right.\\left { {{xgeq5 } atop {2x^{2}-14x+25>0 }} right.$

2x² - 14x + 25 =0

D < 0 , решений нет

Окончательный ответ : x ∈ [0 ; 4 ]

0 + 1 + 2 + 3 + 4 = 10