Question

даю 21 балл помогите по химии срочно прошу

Answer 1

1)

дано

m(Cu2(OH)2CO3) = 444 g

-----------------------------------

m(CuO)-?

m(CO2)-?

m(H2O)-?

Cu2(OH)2CO3-->2CuO+H2O+2CO2

M(Cu2(OH)2CO3) = 222 g/mol

n(Cu2(OH)2)CO3) = m/M = 444 / 222 = 2 mol

n(Cu2(OH)2)CO3) = n(H2O) = 2 mol

M(H2O) = 18 g/mol

m(H2O) = n*M = 2*18  = 36 g

n (Cu2(OH)2)CO3) = 2n(CuO) = 2n(CO3)

n(CO3) = 2*2 = 4 mol

M(CuO) = 80 g/mol

m(CuO) = n*M = 80*4 = 320 g

n(CO2) = 2*2 = 4 mol

M(CO2) = 44 g/mol

m(CO2) = n*M = 4* 44 = 176 g

ответ 320 г, 176 г, 36г .

2)

дано

m(Fe) = 28 g

----------------------

m(Fe3O4)-?

Fe3O4+4H2-->3Fe+4H2O

M(Fe) = 56 g/mol

n(Fe) = m/M = 28 / 56 = 0.5 mol

n(Fe3O4) = 3n(Fe)

n(Fe3O4) = 0.5 / 3 = 0.17 mol

M(Fe3O4) = 232 g/mol

m(Fe3O4) = n*M = 0.17 * 232 = 39.44 g

ответ 39.44 г

3)

дано

m(KCLO3) = 1.225 g

------------------------------

m(KCL)-?

m(O2)-?

2KCLO3--t-->2KCL+3O2

M(KCLO3) = 122.5 g/mol

n(KCLO3) = m/M = 1.225 / 122.5 = 0.01 mol

2n(KCLO3) = 2n(KCL) = 0.01 mol

M(KCL) = 74.5 g/mol

m(KCL) = n*M = 0.01*74.5 = 0.745 g

2n(KCLO3) = 3n(O2)

n(O2) = 3*0.01 / 2 = 0.015 mol

M(O2) = 32 g/mol

m(O2) = n*M = 0.015 * 32 = 0.48 g

ответ 0.745 г , 0.48 г

4)

дано

m(Zn) = 26 g

----------------------

m(HCL)-?

n(HCL)-?

M(Zn) = 65 g/mol

n(Zn) = m/M = 26 / 65 = 0.4 mol

2HCL+Zn-->ZnCL2+H2

2n(HCL) = n(Zn)

n(HCL) = 2*0.4 = 0.8 mol

M(HCL) =36.5 g/mol

m(HCL) = n*M =0.8 * 36.5 = 29.2 g

ответ 29.2 г , 0.8 моль