Question

найдите нули функции y=2sin(2x-pi/3)

Answer 1

$y=2 sin (2x-pi /3)\\2sin (2x-pi/3)=0\sin (2x-pi/3)=0\\2x-dfrac{pi}{3}=pi k, quad  k in mathbb Z\\2x= dfrac{pi}{3}+pi k, quad k in mathbb Z \\x=dfrac{pi}{6}+dfrac{pi k }{2}, quad k in mathbb Z$