Question

1/28 √196 + 10 √0,49

√1 11/25 - √0,04

( 0,8/√32 )

Answer 1

$1)frac{1}{28}sqrt{196}+10sqrt{0,49}=frac{1}{28}*14+10*0,7=frac{1}{2}+7=7,5\\2)sqrt{1frac{11}{25}} -sqrt{0,04}=sqrt{frac{36}{25} }-0,2=frac{6}{5}-0,2=1,2-0,2=1\\3)frac{0,8}{sqrt{32} }=frac{0,8}{4sqrt{2} }=frac{0,2}{sqrt{2} }=frac{0,2sqrt{2} }{2}=0,1sqrt{2}$