Question

Решить данные задачи

Answer 1

1)по т. Пифагора
${ac}^{2} = {ab}^{2} + {bc}^{2} = 36 + 64 = 100 \ ac = 10$
2по т. Пифагора
${mn}^{2} = {km}^{2} - {kn}^{2} = 169 - 144 = 25 \ mn = 5$
3
${df}^{2} = {de}^{2} + {fe}^{2} = 49 + 25 = 74 \ df = sqrt{74}$
4
${pr}^{2} = {or}^{2} - {op}^{2} = 81 - 49 = 32 \ pr = sqrt{32} = 4 sqrt{2}$