Question

Помогите пожалуйста
$x^{2}dy+(y-1)dx=0$

Answer 1

$x^2dy + (y - 1)dx = 0\x^2dy = (1 - y)dx\frac{dy}{1 - y} = frac{dx}{x^2}\int frac{dy}{1 - y} = int frac{dx}{x^2}\-ln(1 - y) = -frac{1}{x} + c_1\y - 1 = c_2e^{frac{1}{x}}, quad (c_2 = e^{c_1})\y = 1 + c_2e^{frac{1}{x}}$