Question

найдите функцию,обратную функции y = 3 - x^2? x>=0. 

Answer 1

$y = 3 - x^2 \ x^2=3-y \ x= sqrt{3-y} \\ y= sqrt{3-x}$

Answer 2

$y=3-x^2; x geq 0$
=>$y<=3; 3-y geq 0$

$y(x)=3-x^2$
$x^2=3-y$
$x=sqrt{3-y}$
$x(y)=sqrt{3-y}$
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$y(x)=sqrt{3-x}$ - обратная