Question

Помогите, пожалуйста, решить уравнения

Answer 1

$sqrt[3]{24 + sqrt{ {x}^{2} + 5 } } = 3\ 24 + sqrt{ {x}^{2} + 5} = 27 \ sqrt{x {}^{2} + 5} = 27 - 24 = 3 \ {x}^{2} + 5 = 9 \ {x}^{2} = 4 \ x1 = 2 \ x2 = - 2$
$sqrt{11 - sqrt[3]{ {x}^{2} + 7 } } = 3 \ 11 - sqrt[3]{ {x}^{2} + 7} = 9 \ sqrt[3]{ {x}^{2} + 7 } = 2 \ {x }^{2} + 7 = 8 \ {x}^{2} = 1 \ x1 = 1 \ x2 = - 1$
$5 - x - sqrt{x + 7} = 0 \ 5 - x = sqrt{x + 7} \ 25 - 10x + {x}^{2} = x + 7 \ {x }^{2} - 11x + 18 = 0 \ x1 = 9 \ x2 = 2$
x1 не подходит. т. к х<=5