Question

$sin^{6}+cos^{6}=sin^{2} cos^{2}$

Answer 1

$(sin^2 x +cos^2 x)(sin^4 x-sin^2 xcos^2 x+cos^4 x)=sin^2 xcos^2 x\sin^4 x-2sin^2 xcos^2 x+cos^4 x=0\(cos^2 x-sin^2 x)^2=0\cos 2x=0\2x=pi /2 +pi k\x=pi /4+pi k/2$