Question

1/3tg3x=-корень из 3/3

Answer 1

$frac{1}{3} tg3x=-frac{sqrt{3} }{3}$

$tg3x=-frac{sqrt{3} }{3} :frac{1}{3}$

$tg3x=-frac{sqrt{3} }{3} *3$

$tg3x=-sqrt{3}$

$3x=arctg(-sqrt{3})+pi n,$  $n$ ∈ $Z$

$3x=-arctgsqrt{3}+pi n,$  $n$ ∈ $Z$

$3x=-frac{pi}{3} +pi n,$  $n$ ∈ $Z$

$x=-frac{pi}{9} +frac{pi n }{3} ,$  $n$ ∈ $Z$