Question

помогите с алгеброй 7 класч

Answer 1

Здравствуйте!

1)
$5 + x {}^{2} = (x + 11)(x - 6) - x \ 5 + x {}^{2} = x {}^{2} + 4x - 66 \ - 4x + 66 + 5 = 0 \ - 4x + 71 = 0 \ - 4x = - 71 \ 4x = 71 \ x = 17.75$
2)
$frac{4x + 3}{4} - frac{7x + 1}{8} = 2 \ \ 2(4x + 3) - (7x + 1) = 16 \ 8x + 6 - 7x - 1 - 16 = 0 \ x - 11 = 0 \ x = 11$
3)
$(n - 4)(n + 39) - (n - 3)(n + 31) = \ = n {}^{2} + 35n - 156 - n {}^{2} + 28n - 93 = \ = 63n - 249$