Question

30^0.8 * 6^0.2 : 5^-1.2 =

все под корнем (578^2 - 480^2) =

a^1.2 : a^1.7 при a = 4

помогите решить , буду благодарен

Answer 1

${30}^{0.8} times {6}^{0.2} div {5}^{ - 1.2} = {30}^{ frac{4}{5} } times {6}^{ frac{1}{5} } div {5}^{ - frac{6}{5} } = sqrt[5]{ {30}^{4} } times sqrt[5]{6} times {5}^{ frac{6}{5} } = sqrt[5]{ {5}^{4} times {6}^{4} times 6 times {5}^{6} } = sqrt[5]{ {5}^{10} times {6}^{5} } = {5}^{2} times 6 = 25 times 6 = 150$

▪

$sqrt{ {578}^{2} - {480}^{2} } = sqrt{(578 - 480)(578 + 480)} = sqrt{98 times 1058} = sqrt{ {7}^{2} times 2 times {23}^{2} times 2} = 7 times 23 times 2 = 322$

▪

${a}^{1.2} div {a}^{1.7} = {a}^{ - 0.5} = {a}^{ - frac{1}{2} } = frac{1}{ sqrt{a} } = frac{1}{ sqrt{4} } = frac{1}{2} = 0.5$

Answer 2

Огромное спасибо вам !

Answer 3

рада помочь. удачи!!!