Question

sin 2(t-3П/2)cos 2(2П-t) : tg 2(t-п/2)cos 2(t-3п/2)

Answer 1

$frac{sin^2(t-frac{3pi}{2}), cos^2(2pi -t)}{tg^2(t-frac{pi }{2}), cos^2(t-frac{3pi }{2})}=frac{cos^2tcdot cos^2t}{ctg^2tcdot sin^2t}=frac{cos^4t}{frac{cos^2t}{sin^2t}cdot sin^2t}=cos^2t$