Question

f(x)=3x-1/9x^2-1

решите пожалуйста

Answer 1

х=$frac{3x-1}{9x^{2} -1 }$ =  x = $frac{3x-1}{9x^{2} -1}$, х≠$frac{1}{3}$, х≠$-frac{1}{3}$

х =  $frac{3x-1}{(3x-1)* (3x+1)}$

x = $frac{1}{3x+1}$

(3x+1) x=1

(3x+1) x-1 =  0

3x²+x=-1=0

x= $frac{-1+-sqrt{1^{2} - 4*3*(-1)} }{2*3}$

x = $frac{-1+-sqrt{1+12} }{6}$

x = $frac{-1+-sqrt{13} }{6}$

$x=frac{-1+sqrt{13} }{6}$

$x = frac{-1-sqrt{13} }{6}$, х≠$frac{1}{3}$, х≠-$frac{1}{3}$

х = $frac{-1+sqrt{13} }{6}$

х = $frac{-1-sqrt{13} }{6}$

х₁ = $frac{-1-sqrt{13} }{6}$, х₂ = $frac{-1+sqrt{13} }{6}$