Question

Найти угол между векторами q и p

Answer 1

p=4b-3a={-12;-10;-15}
q=4a-3b={16;11;27)
$cos alpha = frac{a*b}{|a|*|b|}$
$cos alpha = frac{-12*16+(-10)*11+(-15)*27}{((-12)^2+(-10)^2+(-15)^2)^ frac{1}{2}(16^2+11^2+27^2)^ frac{1}{2} }$