Question

2x^2 - 3y^2 = 5xy - 5

Answer 1

2x^2-5xy-3y^2=

=2x^2-6xy+xy-3y^2=

= (2x^2-6xy)+(xy-3y^2)=

=2x(x-3y)+y(x-3y)=

=(x-3y)(2x+y)

Answer 2

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Answer 3

сколько пар целых чисел подходят