Question

Помогите
log(3) (6x-10)-log(3) 2=log(3) 7

Answer 1

ОДЗ :

6x - 10 > 0

6x > 10

x > 1 2/3

$log_{3}(6x-10)-log_{3}2=log_{3}7\\log_{3}(6x-10)=log_{3}7+log_{3}2\\log_{3}(6x-10)=log_{3}14\\6x-10=14\\6x=24\\x=4$

Ответ : 4