Question

Срочно найдите производнкю функции

Answer 1

y'=(³√(1+x√(x+3))'=1/3 *(1+x√(x+3))^(1/3-1)

*(√(x+3)+x*(√(x+3))'=

1/(3*(1+x√(x+3))^(2/3) *(√(x+3)+x *1/(2√(x+3))=
1/(3(1+x√(x+3))^(2/3) *
(2x+3)/(2√(x+3)

Answer 2

(2х+3)/2(√(х+3)) надо (3х+6)/(2√(х+3)

Answer 3

$y=sqrt[3]{1+xsqrt{x+3}}=Big (1+xsqrt{x+3}Big )^{frac{1}{3}}\\y'=frac{1}{3}cdot Big (1+xsqrt{x+3}Big)^{-frac{2}{3}}cdot Big (sqrt{x+3}+xcdot frac{1}{2sqrt{x+3}}Big )=\\=frac{1}{3cdot sqrt[3]{(1+xsqrt{x+3})^2}}cdot frac{2(x+3)+x}{2sqrt{x+3}}=frac{1}{sqrt[3]{(1+xsqrt{x+3})^2}}cdot frac{x+1}{2sqrt{x+3}}$

Answer 4

помоте пожалуйста https://znanija.com/task/31169129

Answer 5

последний ( х+1) надо (х+2)

Answer 6

да