Question

Помогите пожалуйста 2 задание сделать

Answer 1

$- 0.2 {x}^{2} + 4 = 0 \ - 0.2 {x}^{2} = - 4 \ {x}^{2} = - 4 div ( - 0.2) \ {x }^{2} = 20 \ x1 = - 2 sqrt{2} \ x2 = 2 sqrt{2}$
$frac{ {x}^{2} }{3} + frac{x}{9} = 0 \ frac{1}{3} x(x + frac{1}{3} ) = 0 \ x = 0 \ x = - frac{1}{3}$
${(2x - 1)}^{2} = 1 - 4x \ 4 {x}^{2} - 4x + 1 = 1 - 4x \ 4 {x}^{2} = 0 \ x = 0$
$3 - (4x + 1)(3 - x) = x \ 3 - 12x + 4 {x}^{2} - 3 + x = x \ 4 {x}^{2} - 12x = 0 \ 4x(x - 3) = 0 \ x = 0 \ x = 3$
$3 - 0.4 {x}^{2} = 0 \ 0.4 {x}^{2} = 3 \ {x}^{2} = 7.5 \ x = - frac{ sqrt{30} }{2} \ x = frac{ sqrt{30} }{2}$
$frac{ {x}^{2} }{4} - frac{x}{2} = 0 \ frac{x}{2} ( frac{x}{2} - 1) = 0 \ x = 0 \ x = 2$
${(3x + 2)}^{2} = 4 + 12x \ 9 {x}^{2} + 12x + 4 = 4 + 12x \ 9 {x}^{2} = 0 \ x = 0$
${x}^{2} - (2x - 3)(1 - x) = 0 \ {x }^{2} - 2x + 2 {x}^{2} + 3 - 3x = 0 \ 3 {x}^{2} - 5x + 3 = 0 \ net : otweta$