• Предмет: Алгебра
  • Автор: irinasmile88
  • Вопрос задан 8 лет назад

Решите, пожалуйста, срочно!
Даю 25 баллов!!

Приложения:

Ответы

Ответ дал: arazikgeldimyradow
0

 {(15a {b}^{2} )}^{2}
 {(3c {d}^{2}) }^{3}
 {(4 {a}^{4}b) }^{2}

 {(12 {x}^{4}y) }^{2}
 {(9m {n}^{4} )}^{2}
 {(0.2 times 5)}^{9}  =  {1}^{9}  = 1
( frac{3}{7}  times frac{7}{3})^{21}   =  {1}^{21}
 frac{ {7}^{6} times  {3}^{6} }{ {21}^{5} }  =  frac{ {21}^{6} }{ {21}^{5} }  = 21


 {2}^{ - 2 + ( - 2)}  =  {2}^{ - 4}
 {( frac{1}{7}  times 7)}^{ - 2}  =  {1}^{ - 2}  = 1
 {2 }^{ - 3 + ( - 7) - ( - 5) - ( - 4)}  =  {2}^{ - 1}  = 0.5
 {( - 4)}^{ - ( - 2)}  times  {2}^{ - 3}  =  {4}^{2}  times  {4}^{ -  frac{3}{2} }  =  {4}^{ frac{1}{2} }  = 2
 frac{ {3}^{ - 5} times  {3}^{ - 2}  }{ {3}^{ - 8} }  =  {3}^{ - 5 +  ( - 2) - ( - 8)}  =  {3}^{1}  = 3
 {3}^{ - 2 + 3}  =  {3}^{1}  = 3
 {5}^{ - ( - 2)}  times  {5}^{3}  times  {5}^{ - 4}  =  {5}^{2 + 3 - 4} =  {5}^{1}   = 5
(0.2) =  {5}^{ - 1}  \  {(0.2)}^{ - 3} =  {5}^{ - ( - 3)}   =  {5}^{3}  = 125
 frac{ {7}^{ - 3 times ( - 2)} times  {7}^{ - 5}  }{ {7}^{ - 2 + 3} } =  frac{ {7}^{6 - 5} }{7}   =  frac{7}{7}  = 1
 {(5)}^{ - ( - 2)}  times  {5}^{ - 3}  times  {5}^{ - 2}  =  {5}^{2 - 3 - 2} =  {5}^{ - 3} = 0.008
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