Question

Помогите решить!!!!!!!!!

Answer 1

$3x^{2} +2x-1=0\D= b^{2} -4ac = 4-4*3*(-1) = 4-(-12)=4+12=16\x1,2= frac{-b+-sqrt{D} }{2a} = frac{-2+-4}{6}\x1=2/6=1/3\x2=-6/6=-1$

Дискриминант равен 16