Question

решите 21 плииизпрошуу

Answer 1

$tt36(x-8)=(x-8)^3\6^2cdot(x-8)-(x-8)^3=0\(x-8)(6^2-(x-8)^2)=0\(x-8)(6-(x-8))(6+x-8)=0\(x-8)(6-x+8)(x-2)=0\(x-8)(14-x)(x-2)=0\\ x-8=0; 14-x=0; x-2=0\x_1=8; x_2=14; x_3=2$