Question

$frac{4}{ x -1} - frac{4}{x + 1} = 1$
Помогите с алгеброй пожалуйста, срочно

Answer 1

$frac{4}{x-1}-frac{4}{x+1}=1; ; ,qquad ODZ:; xne -1; ,; xne 1\\frac{4(x+1)-4(x-1)-(x-1)(x+1)}{(x-1)(x+1)}=0\\frac{4x+4-4x+4-x^2+1}{(x-1)(x+1)}=0\\frac{-x^2+9}{(x-1)(x+1)}=0; ; Rightarrow ; ; left { {{-x^2+9=0} atop {xne 1; ,; xne -1}} right. \\-x^2+9=0; ; ,; ; x^2-9=0; ; ,\\(x-3)9x+3)=0\\underline {x_1=3; ,; ; x_2=-3}$

Answer 2

4/(x-1)-4/(x+1)=1 , x≠1,x≠-1

(4(x+1)-4(x-1))/(x-1)(x+1) = 1

(4x+4-4x+4)/(x-1)(x+1)=1

8/(x²-1)=1

x²-1=8

x²=8+1

x²=9

a)/x/=3, x1=3, x2=-3

b)x²-9=0, (x+3)(x-3)=0

  x-3=0, x1=3

 x+3=0, x2=-3