Question

решите через дискриминант и найдите x1,2. потом просто x1 x2

Answer 1

$a)3 {x}^{2} + 13x - 10 = 0 \ d = 169 + 3 times 4 times 10 = 289 \ x1 = frac{ - 13 + 17}{6} = frac{4}{6} = frac{2}{3} \ x2 = frac{ - 13 - 17}{6} = - 5 \ b)2 {x}^{2} - 3x = 0 \ x(2x - 3) = 0 \ x1 = 0 : : : x2 = frac{3}{2} = 1.5 \ v)16 {x}^{2} = 49 \ 16 {x}^{2} - 49 = 0 \ (4x - 7)(4x + 7) = 0 \ 4x - 7 = 0 : : : : : : : : : : : : : : : 4x + 7 = 0\ x 1 = frac{7}{4} = 1 frac{3}{4} : : : : : : : : x2 = - frac{7}{4} = - 1 frac{3}{4} \ r) {x }^{2} - 2x - 35 = 0 \ x1 = 7 \ x2 = - 5$