Question

РЕШИТЕ УРАВНЕНИЕ!
$(x^2+1)^2 - 6(x^2+1)^2+5=0$

Answer 1

$( { {x}^{2} + 1)}^{2} - 6( { {x}^{2} + 1)}^{2} + 5 = 0 \ {x}^{4} + 2 {x}^{2} + 1 - 6({x}^{4} + 2 {x}^{2} + 1) + 5 = 0 \ {x}^{4} + 2 {x}^{2} + 1 - 6 {x}^{4} - 12 {x}^{2} - 6 + 5 = 0 \ - 5 {x}^{4} - 10 {x}^{2} + 0 = 0 \ - 5 {x}^{2} times ( {x}^{2} + 2) = 0 \ {x}^{2} times ( {x}^{2} + 2) = 0 \ {x}^{2} = 0 \ {x}^{2} + 2 = 0 \ x = 0$
x∉R
Ответ: x=0