Question

пж помогите 8 класссс

Answer 1

Здравствуйте!

Вот ваше решение:

$6x^{2}- 18 = 0 \x^{2}- 3 = 0\x^{2} = 3\x= -sqrt{3}\x= sqrt{3} \x_{1}= -sqrt{3} \x_{2} = sqrt{3} \\y^{2}- 5y = 0\y *(y-5) = 0\y = 0\y - 5 = 0\y = 0\y = 5\y_{1} = 0\y_{2} = 5 \\x^{2}-6x + 5 = 0\ x^{2} -x -5x +5 = 0\x*(x-1)-5(x-1)=0\(x-1)*(x-5)= 0\x-1 = 0\x-5=0 \x=1\x= 5\x_{1}= 1\x_{2} = 5\\10x^{2} -3x - 0.4 = 0\50x^{2} -15x -2 = 0\50x^{2} + 5x - 20x - 2 = 0\5x*(10x+1) - 2(10x+1) = 0\(10x+1)*(5x-2)=0\10x + 1 = 0\ 5x - 2 = 0\ x = -frac{1}{10}\ x= frac{2}{5}$