Question

(х-3)^2+(х-4)^2=5
Помогите

Answer 1

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Применим формулу квадрата разности:

${(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2}$
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${(x - 3)}^{2} + {(x - 4)}^{2} = 5 \ {x}^{2} - 6x + 9 + {x}^{2} - 8x + 16 = 5 \ 2 {x}^{2} - 14x + 20 = 0 \ {x}^{2} - 7x + 10 = 0$

D = 49 - 4•10 = 9

x1 = ( 7 - 3 )/2 = 4/2 = 2


x2 = ( 7 + 3 )/2 = 10/2 = 5



ОТВЕТ: 2 ; 5

Answer 2

https://znanija.com/task/31260764