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Применим формулу квадрата разности:
![{(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \ \ {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \ \](https://tex.z-dn.net/?f=+%7B%28a+-+b%29%7D%5E%7B2%7D++%3D++%7Ba%7D%5E%7B2%7D++-+2ab+%2B++%7Bb%7D%5E%7B2%7D++%5C++%5C+)
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![{(x - 3)}^{2} + {(x - 4)}^{2} = 5 \ {x}^{2} - 6x + 9 + {x}^{2} - 8x + 16 = 5 \ 2 {x}^{2} - 14x + 20 = 0 \ {x}^{2} - 7x + 10 = 0 \ {(x - 3)}^{2} + {(x - 4)}^{2} = 5 \ {x}^{2} - 6x + 9 + {x}^{2} - 8x + 16 = 5 \ 2 {x}^{2} - 14x + 20 = 0 \ {x}^{2} - 7x + 10 = 0 \](https://tex.z-dn.net/?f=+%7B%28x+-+3%29%7D%5E%7B2%7D++%2B++%7B%28x+-+4%29%7D%5E%7B2%7D++%3D+5+%5C++%7Bx%7D%5E%7B2%7D++-+6x+%2B+9+%2B++%7Bx%7D%5E%7B2%7D++-+8x+%2B+16+%3D+5+%5C+2+%7Bx%7D%5E%7B2%7D++-+14x+%2B+20+%3D+0+%5C++%7Bx%7D%5E%7B2%7D++-+7x++%2B+10+%3D+0+%5C++)
D = 49 - 4•10 = 9
x1 = ( 7 - 3 )/2 = 4/2 = 2
x2 = ( 7 + 3 )/2 = 10/2 = 5
ОТВЕТ: 2 ; 5
Применим формулу квадрата разности:
=========================================
D = 49 - 4•10 = 9
x1 = ( 7 - 3 )/2 = 4/2 = 2
x2 = ( 7 + 3 )/2 = 10/2 = 5
ОТВЕТ: 2 ; 5
Ответ дал:
0
https://znanija.com/task/31260764
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