Question

Разложить на множители: x^6-x^4-x^2+1

Answer 1

x⁶-x⁴-x²+1=x⁴(x²-1)-(x²-1)=(x⁴-1)(x²-1)=(x²-1)(x²+1)(x-1)(x+1)=(x²+1)(x-1)²(x+1)²

Answer 2

x^4*(x^2-1)-(x^2-1)

x^4*(x-1)*(x+1)-(x-1)*(x+1)

(x-1)*(x+1)*(x^4-1)

(x-1)*(x+1)*(x^2-1)*(x^2+1)

(x-1)*(x+1)*(x-1)*(x+1)*(x^2+1)

(x-1)^2*(x+1)^2*(x^2+1)