Question

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y^2+1,4y+0,49−36y^2=0

Answer 1

Здравствуйте!

Вот ваше решение:

$y^{2} +1.4y + 0.49 - 36y^{2} =0\-35y^{2} +frac{7}{5} + frac{49}{100} = 0\-3500y^{2}+140y+49=0\ 500y^{2}-20y-7=0\ 500y^{2} +50y-70y-7=0\50y(10y+1)-7(10y+1)=0\(10y+1)(50y-7)=0\10y + 1 =0\50y - 7 = 0\y_{1} = -frac{1}{10} = -0.1\y_{2} = frac{7}{50} = 0.14$

Answer 2

https://znanija.com/task/31280340, помогите 50 баллов с алгеброй