Question

Помогите пожалуйста
{x-√y=2; x^2-y=10

Answer 1

$left { {{x-sqrt{y}=2} atop {x^2-y=10}} right.\ \ left { {{x-sqrt{y}=2} atop {x^2-(sqrt{y})^2=10}} right. \ \ left { {{sqrt{y} =x-2} atop {x^2-(x-2)^2=10}} right. \ \ left { {{sqrt{y} =x-2} atop {x^2-(x^2-4x+4)=10}} right. \ \ left { {{sqrt{y} =x-2} atop {x^2-x^2+4x-4=10}} right. \ \ left { {{sqrt{y} =x-2} atop {4x=14}} right. \ \ left { {{sqrt{y} =frac{7}{2}-2} atop {x=frac{7}{2}}} right.$

$left { {{sqrt{y}=1.5} atop {x=frac{7}{2}}} right. \ \ left { {{y=2.25} atop {x=frac{7}{2}}} right.$

Ответ: (7/2; 2.25)