Question

(3x+1)²-(3x-2)(2+3x)=17

Answer 1

$9x^{2} +1-6x+9x-4-6x=17\9x^{2} +1-6x+9x-4=17\9x^{2} -12x +9x=17+1-4\9x^{2} -3x=14\x(9x-3)=14\x=14,9x=14+3\9x=17\x=17:9\x=1.9\9*1.9-3=14.1$