Question

ПОМОГИТЕ!!!АЛГЕБРА 8 КЛАСС!!!СРОЧНО!!!

Answer 1

1.
а)
$6 sqrt{1 times frac{7}{9} } - 4 = 6 sqrt{ frac{16}{9} } - 4 = 6 times frac{4}{3} - 4 = 2 times 4 - 4 = 8 - 4 = 4$
б)
$sqrt{7.2} times sqrt{20} = sqrt{0.36 times 20} times sqrt{20} = 0.6 times 20 = 12$
в)
$frac{ sqrt{216} }{ sqrt{6} } = frac{ sqrt{6} sqrt{36} }{ sqrt{6} } = sqrt{36} = 6$
г)
$sqrt{ {5}^{4} times {3}^{2} } = {5}^{2} times 3 = 25 times 3 = 75$
2.
а)
$4 sqrt{20} - sqrt{125} = 4 sqrt{4 times 5} - sqrt{25 times 5} = 8 sqrt{5} - 5 sqrt{5} = 3 sqrt{5}$
б)
$(3 sqrt{6} + sqrt{12} ) sqrt{3} = (3 sqrt{6} + sqrt{4 times 3}) sqrt{3} = (3 sqrt{6} + 2 sqrt{3} ) sqrt{3} = 3 sqrt{18} + 6 = 3 sqrt{9 times 2} + 6 = 9 sqrt{2} + 6$
в)
${(5 - sqrt{2)} }^{2} = {5}^{2} - 2 times 5 sqrt{2} + { sqrt{2} }^{2} = 25 - 10 sqrt{2} + 2 = 27 - 10 sqrt{2}$
3.
а)
$12 sqrt{3} = sqrt{144 times 3} = sqrt{432}$
б)
$- 9 sqrt{2} = - sqrt{81 times 2} = - sqrt{162}$
4.
$sqrt{ {x}^{2} - 6x + 9 } = sqrt{ {(x - 3)}^{2} } = |x - 3|$
|2.6 - 3| = |-0.4| = 0.4

Дальше сама. :)

Answer 2

4. =|х-3|=|2,6-3|=|-0,4|=0,4

Answer 3

Точно! Спасибо, исправила. :)

Answer 4

спасибо;3