Question

69-(13-у)степ2=-у
степ2

Answer 1

Здравствуйте!

Вот ваше решение:

$69-(13-y)^{2} = -y^{2} \69-(169-26y+y^{2} )=-y^{2} \69-169+26y-y^{2}= -y^{2} \69-169+26y = 0\-100+26y = 0\26y = 100\y = frac{50}{13} \y = 3frac{11}{13}$