Question

Срочно !!! 7 класс !!

Answer 1

1.

a)

$(6x-5xy)-(4x+xy)=6x-5xy-4x-xy=2x-6xy$

b)

$3ac^3(5c^2-a)=15ac^5-3a^2c^3$

2.

$(6x-16+x^2)-x(x-4)=24$

$6x-16+x^2-x^2+4x=24$

$6x+x^2-x^2+4x=24+16$

$10x=40 /:10$

$x=4$

Answer 2

(6x-5xy)-(4x+xy)=(x(6-5y))-x(4+y)=x(6-5y)-x(4+y)=x(6-5y-(4+y))=x(6-5y-4-y)=x(2-6y)=x*2(1-3y)=2x(1-3y)

3ac³(5c²-a)=3ac³*5c²-3ac³a=15ac^5 -3a²c³

$(6x - 16 + {x}^{2} ) - x(x - 4) = 24 \ \ 6x - 16 + {x}^{2} - {x}^{2} + 4x = 24 \ \ 10x - 16 = 24 \ \ 10x = 24 + 16 \ \ 10x = 40 \ \ x = 4$