Question

1) (x-5)(x-2)=
2) (3a-2)(4a-2)
3)(6x+a)(2x-3a)=
срочно!!

Answer 1

1)(x-5)(x-2)=x²-2x-5x+10=x(x-2)-5(x-2)=(x-5)(x-2)
2)(3a-2)(4a-2)=12a²-6a-8a+4=6a(2a-1)-4(2a-1)=(6a-4)(2a-1)
3)(6x+a)(2x-3a)= 12x²-18xa+2xa-3a²=2x(6x+a)-3a(6x+a)=(2x-3a)(6x+a)