Question

Помогите решить - 2 вариант;

Answer 1

$1)15ab - 5 {b}^{2} - 15ab - 3 {a}^{2} = \ - 5 {b}^{2} - 3 {a}^{2}$
$b) {2a}^{3} - 3an - 2 {n}^{3} - an = \ 2 {a}^{3} - 4an - {2n}^{3}$
$2)a)40 - 88 + 16x = 15x - 12 \ - 48 + 16x - 15x + 12 = 0 \ x - 36 = 0 \ x = 36$
$b)3(2 - x) - x = 5 \ 6 - 3x - x = 5 \ 6 - 4x = 5 \ 4x = 6 - 5 = 1$
$x = 1 div 4 = frac{1}{4}$