Question

Помогите решить под 4)

Answer 1

$left { {{x^{3}y^{3}+x^{2}y^{4}=12} atop {x^{4}y^{2}+x^{3}y^{3} =24}} right. \\:left { {{x^{2}y^{3}(x+y)=12} atop {x^{3}y^{2}(x+y)=24}} right.\--------\\frac{y}{x}=frac{1}{2}\\x=2y\\(2y)^{3}*y^{3}+(2y)^{2}*y^{4}=12\\8y^{3}*y^{3}+4y^{2}*y^{4}=12\\8y^{6}+4y^{6}=12\\12y^{6}=12\\y^{6} =1\\y_{1}=1\\y_{2}=-1\\x_{1}=2*1=2\\x_{2}=2*(-1)=-2$

Ответ : (2 ; 1) , ( - 2 ; - 1)