Question

a^2+2a+1
b^2-8b+16
c^2+10c+25
n^2+14n+49
100-20z+z^2
представьте в виде многочлена

Answer 1

${a}^{2} + 2a + 1 = ( {a + 1)}^{2} \ {b}^{2} - 8b + 16 = ( {b - 4)}^{2} \ {c}^{2} + 10c + 25 = ( {c + 5)}^{2} \ {n}^{2} + 14n + 49 = ( {n + 7)}^{2} \ 100 - 20z + {z}^{2} = ( {10 - z)}^{2}$