Question

Решите Уравнение:
(x+9)^2-x*(x+8)=1
(x-11)^2=(x-7)*(x-9)
(x-4)*(x+4)-(x+6)^2=-16
(1-3x)^2-x*(9x-2)=5

Answer 1

здравствуй.

$boxed{1}\\(x+9)^2-x*(x+8)=1\x^2+18x+81-x^2-8x-1=0\10x+80=0\10x=-80\x=-8\\boxed{2}\\(x-11)^2=(x-7)*(x-9) \x^2-22x+121=x^2-16x+63\x^2-22x+121-x^2+16x-63=0\-6x=-58\x=9frac{2}{3} \\boxed{3}\\(x-4)*(x+4)-(x+6)^2=-16\x^2-16-x^2-12x-36+16=0\-36-12x=0\-12x=36\x=-3\\boxed{4}\\(1-3x)^2-x*(9x-2)=5\9x^2-6x+1-9x^2+2x-5=0\-4x-4=0\-4x=4\x=-1$

удачи в учебе.