Question

номер 733 помогите!!!!!!

Answer 1

$1)$

$frac{1}{x}+frac{3}{frac{12}{5}x }=[tex]frac{3}{4}$

$xneq 0$

$frac{1}{x}+frac{5}{4x}=frac{3}{4}$

$frac{9}{4x} =frac{3}{4}$

$36=12x$

$x=3$

$2)\frac{1}{x}-frac{3}{7x} =frac{2}{7}$

$frac{4}{7x}=frac{2}{7}$

$28=14x$

$x=2$

$3)\frac{6}{frac{10x}{3} } +frac{1}{x} =frac{2}{5} \frac{9}{5x}=frac{1}{x}=frac{2}{5} \frac{14}{5x}=frac{2}{5} \70=10x \x=7$