Question

1) 4ctg 30° - 6sin 60°
2) 2ctg пи/3 sin пи/3 - cos 2Пи
Помогите срочно !

Answer 1

1) 4ctg30°-6sin60° = 4*√3-6*√3/2=4√3-3√3=√3
2) 2ctg(π/3)sin(π/3)-cos2π=(2√3/3)*(√3/2)-1=1-1=0