Question

Решите пж
8x(x+5)-2x(6x+10)=5

Answer 1

$8x(x + 5) - 2x(6x + 10) = 5 \ 8 {x}^{2} + 40x - 12 {x}^{2} - 20x = 5 \ - 4 {x}^{2} + 20x = 5 \ - 4 {x}^{2} + 20x - 5 = 0 | : : : : times ( - 1) \ 4 {x}^{2} - 20x + 5 = 0 \ d = ( - 20)^{2} - 4 times 4 times 5 = 320 \ \ x1 = frac{20 + sqrt{320} }{2 times 4} \ \ x2 = frac{20 - sqrt{320} }{2 times 4} \ \ x1 = frac{5 + 2 sqrt{5} }{2} \ \ x2 = frac{5 - 2 sqrt{5} }{2}$
Готово.

Answer 2

в x1 в знаменателе двойка