Question

$log_{0.25}64 + log_{5}125$
Вычислите

Answer 1

$log_{0.25}64 + log_{5}125=log_{frac{1}{4}}4^3 + log_{5}5^3=log_{frac{1}{4}}(frac{1}{4})^{-3} + 3log_{5}5=\-3log_{frac{1}{4}}(frac{1}{4})^{-3} + 3=-3+3=0$