Question

Решить $sqrt{x} +sqrt[3]{x} +frac{1}{x}$

Answer 1

$y=sqrt x+sqrt[3]x+frac1x=x^{frac12}+x^{frac13}+x^{-1}\y'=frac12x^{-frac12}+frac13x^{-frac23}-x^{-2}=frac1{2sqrt x}+frac1{3sqrt[3]{x^2}}-frac1{x^2}$